What is the distance the spring compressed?

What is the distance the spring compressed? Topic: Case springs
April 19, 2019 / By Peace
Question: A 150 g block on a frictionless table is firmly attached to one end of a spring with k = 26 N/m. The other end of the spring is anchored to the wall. A 21 g ball is thrown horizontally toward the block with a speed of 5.4 m/s. If the collision is perfectly elastic, what is the maximum compression of the spring? By the way, the ball's speed immediately after collision is 4.1 m/s I have a test tomorrow night any help would begreat!
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Best Answers: What is the distance the spring compressed?

Marilene Marilene | 8 days ago
in this cases, assuming there are energy is in conserved....... firstly,you have to find the kinetic energy of the ball ke=mv^2 ke=(0.021)(5.4)^2 ke=0.61236 j kinetic energy is equal to the elastic potential energy ke=ep 0.61236=0.5kx^2 0.61236/0.5(26)=x^2 x=0.217035977
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Marilene Originally Answered: From where does a jet engine gets its initial compressed air?
There are several different ways to start a jet engine. Some use an electric starter motor. Others use bleed air from another engine, or from an on-board APU, or compressed air from a ground support unit that plugs into the airplane when it's parked on the tarmac. Early military jets even used explosive cartridges like big shotgun shells to get the engine's compressor section spinning. In any case, once the engine is spinning fast enough to provide an adequate supply of compressed air to the burners, fuel is injected into the engine and ignited to create the rapidly expanding flow of hot air that is required to spin the turbines and continue "spooling up" to operating speed.
Marilene Originally Answered: From where does a jet engine gets its initial compressed air?
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Krissy Krissy
Given: mass, m = 0.059 kg top,h = a million.9 meter Spring consistent, ok = 13 N/m Sol'n: rigidity, F = kx This rigidity is with the help of energies being relese unto to the spring. ability ability, PE = mgh PE = 0.059* 9.80 one*a million.9 PE = a million.a million Joules Kinetic ability, KE = 0.5mV^2 V-V0 = gt V0 = 0, preliminary unfastened fall speed. V = 9.80 one t discover t, the full time travelled of the falling mass. y = V0t -0.5gt^2 y =-h, because of the fact under the reference factor. -a million.9 = -0.5(9.80 one)t^2 t = 0.sixty two sec So the suited velovity, V earlier it hits the spring is. V = 9.80 one (0.sixty two) V = 6.a million meter/sec So, KE = 0.5(0.059)(6.a million)^2 KE = a million.a million Joules PE + KE = F*d -----this is the artwork a million.a million + a million.a million = F*d d = x, the spring compression distance. F = kx So, 2.2 = (kx)*x x^2 = 2.2/ok x^2 = 2.2/13 x = 0.411 meter ----this is the gap of spring compression because of the falling mass.
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Krissy Originally Answered: How do you build a car without using chemical reactions, electricity, or compressed gas?
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