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Question about math(all about algebra and coordinates)?

Question about math(all about algebra and coordinates)? Topic: First in math homework
June 26, 2019 / By Anthony
Question: hi guys... I am wondering if you could help me with my math homework... I don't seem to know how to solve these, as i am very poor in math, so, to those who are fortunate enough to be good in math, please do help me, thank you... ^_^ 1. simplify: -2x-(3y+x) - {y-(x+2)} - {2y+(4x-3y)} 2. simplify: 2x^2 -3x -14 / 2x^2 -3x -5 (multiplied by) 2x^2 -x -10 / 2x^2 -5x -7 3. write: (3x^ -6)(9x^2) in simplest form 4. If the coordinates of midpoint of segment joining A(3,1) and B(x,y) are M(2,4) find B(x,y) 5. find the LCM of (2x^2 +x -6) and (2x^2 -5x +3) thanks again guys... ^_^
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Best Answers: Question about math(all about algebra and coordinates)?

Tracy Tracy | 6 days ago
I'm pretty sure you meant those of us who are unfortunate enough to be good in maths 1) first we deal with the ones in the curly brackets{} -2x -3y -x -(y-x-2 -2y-4x+3y) -2x -3y -x -y + x +2 +2y + 4x -3y now we collect the like terms -2x-x +x +4x -3y -y +2y -3y +2 =2x -5y +2 2) to do this we factorise every thing ( don't bother I already did that) (2x-7)(x+2)/(2x-5)(x+1) * (2x-5)(x+2)/(2x-7)(x+1) simplified it gives you (x+2)/(x+1) * (x+2)/(x+1) (x^2 + 4x +4)/(x^2 + 2x +1) 3) By the law of indices 9x^2 = 3x^4 and by another law of indices 3x^ -6 * 3x^4= 3x^ -6 +3 =3x ^ -3 4) normally (3+x)/2 = 2 and (1+y)/2 = 4 so 3 +x =4 and x=1 1+y = 8 y =7 so B=(1,7) 5) to find the LCM you would first factorise them to see if they have any common factor (2x - 3)(x+2) and (2x -1)(x-3) since they don't have any common factor their lcm is their multiplication i.e 4x^4 -8x^3 -11x^2 +33x -18
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We found more questions related to the topic: First in math homework


Tracy Originally Answered: Math homework help - easy algebra?
25k + 12 = -13 In order to get the numbers on one side and the letters on the other first subtract 12 from both sides: 25k = -13 -12 25k = -25 now to get 'k' on it's own, as it is multiplied by 25 we must do the opposite and divide both sides by 25; k = -25 / 25 k = -1 24 + h/4 = 10 So again we want to get the numbers on one side and the letters on the other therefore we must subtract 24 from both sides: h/4 = 10 - 24 h/4 = -14 now as h is being divided by 4, we want to get h on it's own so we must do the opposite and multiply by 4: h = 4 * -14 (*=multiply) h = -56 -9 = 15 + v/3 -9 -15 = v/3 -24 = v/3 -24*3 = v -72 = v v = -72 -17 + q/8 = 13 (add 17 to both sides as it is negative) q/8 = 13 + 17 q/8 = 30 q = 30 * 8 q = 240 8m - 14 = -7 8m = -7 + 14 8m = 7 m = 7/8 m = 0.875 Hope this helps :)
Tracy Originally Answered: Math homework help - easy algebra?
1. 25k = -25 k= -1 2. 24 + h =4 * 10 h = 40 -24 h = 16 3. -9 * 3 = 15 + v -27 - 25 = v v = -52 4. -17 + q = 8 * 13 q = 104 + 17 q = 121 5. 8m = -7 + 14 8m = 7 m = 7/8

Sage Sage
Graph of a Line Graph 3x + 2y = 12. answer to detect the y -intercept, permit x = 0. 3(0) + 2y = 12 2y = 12 Divide the two aspects with the aid of 2. y = 6 further, discover the x-intercept with the aid of letting y = 0 which provides x = 4. ascertain that once x = 2 the result's y = 3. those 3 factors are plotted in discern 7(a). A line is drawn with the aid of them in discern 7(b). no longer each and every line has 2 different intercepts; the graph interior the subsequent occasion does not flow the x-axis, and so it has no x-intercept.
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Neve Neve
-2x-(3y+x) - {y-(x+2)} - {2y+(4x-3y)} = -2x - 3y - x - y + x + 2 - 2y - 4x + 3y = - 6x - 3y + 2 [(2x^2 - 3x -14)/(2x^2 - 3x -5)] x [(2x^2 - x -10)/(2x^2 - 5x -7)]...........factors are the trick here. [(2x-7)(x+2)/(2x-5)(x+1)] x [(2x-5)(x+2)/(2x-7)(x+1)........2x-7 and 2x-5 drop out [(x+2)/(x+1)] x [(x+2)/(x+1)] (x^2 + 4x + 4)/(x^2 + 2x + 1) B(1,7) (2x^2 +x -6) and (2x^2 -5x +3)...........factors again, just the same as with arithmetic (2x-3)(x+2) and (2x-3)(x-1).........The common factor is 2x-3 LCM is (2x - 3)(x + 2)(x - 1).........I'm sure you can multiply this out............
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