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Topic: **trig homework****Question:**
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6-8
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June 21, 2019 / By Frea

6) tan-1(5/12) = A 7) tan A = opp/adj = a/b , tan B = b/a 8) tan62degrees = x/200 therefore, x=376

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6) tan-1(5/12) = A 7) tan A = opp/adj = a/b , tan B = b/a 8) tan62degrees = x/200 therefore, x=376

Simplify: sin14°cos76 ° + cos14°sin76 ° note: sin (a + b) = sin a cos b + cos a sin b so... sin 90º = 1 one problem at a time @ß

sin14°cos76 ° + cos14°sin76 ° = sin(14 + 76) = sin 90 = 1 cos^2 32° - sin^2 32 ° = cos2*(32) = cos 64 cos 120° = cos^2 (120/2) - sin^2 (120/2) = cos^2 (60) - sin^2 (60) = (1/2)^2 - ((sqrt3)/2)^2 = 1/4 - 3/4 = -2/4 = -1/2

sin(14 + 76) = sin(90) = 1 cos(2*32) = cos(64) cos(120) = cos^2(60) - sin^2(60) = (1/4) - (3/4) = -1/2

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