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# Maths Homework Help please?

Topic: **Math homework calculator**July 17, 2019 / By Cristen

**Question:**
Okay guys, year nine maths, lets do this!
Question: A square has diagonals that are 20cm long.
a) remembering that the diagonals of a square bisect each other at right angles, find the area of the square.
b) Calculate the length of the sides of the square from the area you found, correct to two decimal places.
Please show working out and you probably need a calculator :) Thank you sooo much!!!!!!!!!!!! :)) xx

## Best Answers: Maths Homework Help please?

**Bettie | 7 days ago**
Okay, so if the diagonal is 20 cm, then if you drew 2 diagonals, you would get 4 triangles right? So each side of the triangles are 10 cm. So if you use Pythagorean theorem, 10 squared plus 10 squared equals x squared, or 200 = x squared and then find the square root of 200 which equals 14.14. This is also the length of the sides of the square. Area of a square is length squared, which equals 200, remember? So I'm not sure if this is the way you are taught to do it, but that's one way.

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We found more questions related to the topic: **Math homework calculator**

**Originally Answered: Maths Homework, maths genius's please help?**
1. 3x + 2y + 4x - y = (3 + 4)x + (2 - 1)y = 7x + y
3. -2g - g + 3h - 2h = (-2 - 1)g + (3 - 2)h = -3g + h
5. 2x - 4y + 3x - 7y = (2 + 3)x + (-4 - 7)y = 5x + (-11)y = 5x - 11y
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EDIT
Lydzy, please read each line all the way to the end. The final answer doesn't have any brackets. I was showing you the intermediate step(s) because I assumed you didn't know how to "group like terms". But yes, these are simple enough that you can do the grouping in your head, and get the final answer in one step.

**Originally Answered: Maths Homework, maths genius's please help?**
it is straightforward replace a=a million/x b=a million/y c=a million/z replace contained in the equations upload each and all of the equations and you will have something like 2a+2b+2c=... 2a+2(b+c)=... yet b+c=a million/8 replace and discover out a now 2(a+b)+2c=... a+b=a million/9 ... ... ...

**Aideen**
basic, basically do the Distributive belongings, 3(x+4)-2(x+3) First you will could do 3 x "x" and four so 3(x+4) will exchange to (3x+12) And the two(x+3) will exchange to (2x+6) Now you have (3x+12) - (2x+6) which will equivalent X=18 desire this enables!!

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